Lecture 24 - Acid-Base Chemistry

Thursday, April 18, 2024

9:00 AM

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Assignments this week:
﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28698/modules/items/3067394"HW 15 Acids and Bases due Tuesday 4/23
Read Chapter 8
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﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28698/assignments/967954"Final Exam is April 30th at 9:30 AM
The final exam is cumulative and multiple choice


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Today (4/18)
Definitions of Acids and Bases
Conjugate Acids and Bases
[H+], [OH–], Kw, pH, pOH
Acid-Base Reactions
Strong Acids and Bases, Ka, Kb
Titration Calculations
Tuesday (4/23)
Nuclear Chemistry
Next Thursday (4/25)
Final Exam Review
Arrhenius Acids and Bases & Bronsted-Lowry Acids and Bases
An Arrhenius acid may be defined as a Hydrogen containing substance that dissociates on solution in water to produce hydrogen ions H+
In water this ion is generally termed hydronium ion and has the formula H3O+ we sometimes call these protons

While an Arrhenius base may be defined as a substance containing the hydroxide ion that dissociates in water to increase the concentration of this ion OH-

An alternate definition that encompasses more substances is that proposed by Bronsted & Lowry.
A Bronsted-Lowry acid is defined as a hydrogen donor while a Bronsted-Lowry base is defined as a hydrogen acceptor


Examples of acids include: 

Hydrochloric acid (HCl)
Sulfuric acid (H2SO4)
Nitric acid (HNO3)



Examples of bases include:


Sodium hydroxide (NaOH) and any other alkali metal salt
Magnesium hydroxide Mg(OH)2 and any other alkaline earth metal salt (although some are not very soluble)


Some organic molecules (CH containing molecules) can act as acids or bases.
These most notably will contain a carboxylic acids group or an amine group which have the formulas: 





The amino acids that make up the proteins in our bodies contain many of these groups!

Some molecules can behave as both acids and bases. These are termed amphoteric substances and water is just one example we will discuss in a moment.

HSO4-


Dissociation Equations, Strong vs Weak, and Conjugate Acid-Base Pairs
When we write the dissociation of acids and bases in water we can see how the molecule changes to increase the hydrogen or hydroxide concentration:

HCl  →

H2SO4 →                        →

NaOH  →

Ca(OH)2 →


The above examples undergo completion dissociation and are termed strong

However, many acids and bases only undergo partial dissociation and are termed weak In these situations its most appropriate to use the ⇌ arrow and to give an equilibrium constant.
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However, many acids and bases only undergo partial dissociation and are termed weak In these situations its most appropriate to use the ⇌ arrow and to give an equilibrium constant.

Hydrofluoric acid: HF ⇌                                         Ka = 7.2 x 10-4
 
Lactic Acid:           HC3H5O3 ⇌                               Ka = 1.3 x 10-4

Aniline:                  C6H5NH2 ⇌                                  Kb = 4.1 x 10-10

Hypochlorite ion    ClO- ⇌                                        Kb = 3.45 x 10-7


When we write the reaction including another substance we need to define the substances on the left and right side differently.

For each of the following aqueous reactions, identify the acid, base, conjugate acid, and conjugate base.



Untitled picture.png Machine generated alternative text:
(a) H20 + H2C03 = H30 + HC03- 
(b) C5H5NH + H20 C5H5N + H30 
(c) I-ICC)3- + C5H5NH H2C03 + C5H5N 
(d) H20 + HONH3 = HONH2 + 1130 
(e) HOCI + C6H5NH2 OCI- + C6H5NH3 

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Autoionization of water, the Kw equilibrium and Measuring acidity and basicity
Pure water is not completely ion-free as it autoionizes to produce 1 x 10-7 M H+ and 1 x 10-7 M OH-

This can be represented by the equation:                            ⇌                                or                                 ⇌ 

with the equilibrium expression Kw =                             =  


Because the concentration of hydrogen ions varies over a large concentration range, it is often more convenient to use logarithms.


Untitled picture.png Machine generated alternative text:
Kw = [H NOW] 
[H] [OH] 
pH POH 
pH + POH — 14.00 


If [H+] = 1.0 × 10−4 M, find [OH−], pH, and pOH.



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If [OH−] = 4.5 × 10−6 M, find [H+], pH, and pOH.











If pH = 8.00, find [H+], [OH−], and pOH.







The measurement of acidity is done with the help of a pH Probe which measures the concentration of H+ ions


Untitled picture.png Machine generated alternative text:
pH 
POH 
2.4 — 34 
2.9—33 
[OH 1 [OH 
3.5 -4.5 
Grapes 
Tomato & tomato juice 4.2 
Hydrochloric acid 
Sulfuric acid 
Stomach juice 
[xmon juice 
Vinegar 
Apple juice 
Grapefruit juice 
Orange juice 
0.3 
1-3 
1.8-2 
- 3.3 
Sour milk 
White bread 
Acid rain 
Normal rain 
Human saliva 
Drinking water 
Distilled water 
4.3 -4.5 
5-6 
5.2 
5.7 
6.3 — 6.6 
6.5-8 
7.0 
Human blood 
Sea water 
Eggs 
Baking soda 
Borax 
Milk Of magnesia 
Ammoma water 
Lime water 
Soda lye 
7.35 - 7.45 
7.36-8.21 
7.6-8 
8.0 
9.2 
10.5 
11.6 
12.4 
14.0 
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Untitled picture.png Machine generated alternative text:
pH 
POH 
2.4 — 34 
2.9—33 
[OH 1 [OH 
3.5 -4.5 
Grapes 
Tomato & tomato juice 4.2 
Hydrochloric acid 
Sulfuric acid 
Stomach juice 
[xmon juice 
Vinegar 
Apple juice 
Grapefruit juice 
Orange juice 
0.3 
1-3 
1.8-2 
- 3.3 
Sour milk 
White bread 
Acid rain 
Normal rain 
Human saliva 
Drinking water 
Distilled water 
4.3 -4.5 
5-6 
5.2 
5.7 
6.3 — 6.6 
6.5-8 
7.0 
Human blood 
Sea water 
Eggs 
Baking soda 
Borax 
Milk Of magnesia 
Ammoma water 
Lime water 
Soda lye 
7.35 - 7.45 
7.36-8.21 
7.6-8 
8.0 
9.2 
10.5 
11.6 
12.4 
14.0 
Untitled picture.png Machine generated alternative text:
As pH decreases by 1, [W] increases 
As pH decreases by 2, [W] increases 
As pH decreases by n, 
increases 
-fold. 
-fold. 
-fold. 

Writing acid-base reactions involving strong acids and bases and solving Titration problems
When we add an acid to a base we get a neutralization reaction which produces a salt and water 



A titration is a quantitative analysis technique in which a solution of known concentration (titrant) is added to a solution of unknown concentration (analyte) until the reaction is complete (the stoichiometric equivalence point), often when an indicator changes color (the experimental endpoint). 
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A titration is a quantitative analysis technique in which a solution of known concentration (titrant) is added to a solution of unknown concentration (analyte) until the reaction is complete (the stoichiometric equivalence point), often when an indicator changes color (the experimental endpoint). 


A 40.0 mL solution of KOH is neutralized with 34.5 mL of 0.300 M HCl. What is the concentration of the original KOH solution?











A 35.0 mL solution of Sr(OH)₂ is neutralized with 29.5 mL of 0.200 M HNO₃. What is the concentration of the original Sr(OH)₂ solution?















What volume (in milliliters) of 0.120 M HClO₃ are required to neutralize 50.0 mL of 0.150 M NaOH?






Calculate the pH when 25.0 mL of 0.150 M HNO₃ is mixed with 40.0 mL of 0.250 M LiOH.


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