Lecture 10 - Ionic Compounds and Radii

Tuesday, February 13, 2024

1:30 PM

"The most important electrostatic bond is the ionic bond, resulting from the Coulomb attraction of the excess electric charges of oppositely charged ions. The atoms of metallic elements lose their outer electrons easily, whereas those of nonmetallic elements tend to add additional electrons; in this way stable cations and anions may be formed, which may essentially retain their electronic structures as they approach one another to form a stable molecule or crystal." Linus Pauling, The Nature of the Chemical Bond, pg 6.
Class notes can now be found here: https://bricejurban.github.io/CHEM111/
Assignments due this week:
﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28699/assignments/990975"HW 5 - Quantum Part 2 (Aktiv Chemistry) (Fri 2/16)
New Activity: ﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28699/assignments/993257"Emerging Tech in Chemistry
Reading quiz TBD
Reading for today's lecture 5.12, 6.1-6.6
Reading for next lecture 6.7, 7.1-7.4
Office Hours: 
Friday 11-1 CIC 
﷟HYPERLINK "https://calendly.com/bricejurban/office-hours"By appointment

Today's Schedule:
Tuesday (2/13)
Atomic and Ionic Radii
Ionic Bonding
Nomenclature of Metals with Variable Charge Ions
e– Configurations of Transition Metals Ions
Looking Ahead
Thursday (2/15) 
Coulomb's Law
Covalent Bonding
Electronegativity
Lewis Structures Part I
Formal Charge

Ionic Compounds are made of electrostatic (coulombic) attractions
Ionic bonds form between metals and nonmetals
Metals have low ionization energies therefore it is easy to remove electron(s) to form a positively charged cation
Nonmetals have high electron affinities therefore they readily gain electron(s) to form a negatively charged anion
In an ionic bond e-'s are transferred from the metal to the nonmetal. No line is drawn
First Ionization energy equation:         X   ⟶    X+   +   e–
Second Ionization energy equation:     X+   ⟶    X2+   +   e–
First Electron affinity equation:        X    +  e–    ⟶   X– 
Second Electron affinity equation:    X–    +  e–    ⟶   X2– 




Elements
Cation
Anion
Compound
Electron Transfer ⟶ Ionic Bond
 

Mg O








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Ca Cl














 


Al S






    

The common ionic charges of Transition metal ions are determined by the 18-electron rule
When an ion cannot lose or gain electrons to get a full outer electron configuration a relatively stable configuration called the 18-outer electron configuration can be gained instead.
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When an ion cannot lose or gain electrons to get a full outer electron configuration a relatively stable configuration called the 18-outer electron configuration can be gained instead.
Examples: Silver and Thallium















The chemical formula for an Ionic Compound is the simplest electrically neutral set of ions

The total positive charge from the metal cations = the total negative charge from the anions
These ions are arranged in a highly ordered, three-dimensional lattice structure
Due to this arrangement, ionic compounds form crystalline solids
These have very high melting points! It takes a lot of energy to break these compounds.
Ionic compounds are often referred to as salts for their similarities to sodium chloride (Table salt)
Common "salts" include potassium nitrate (KNO₃), magnesium sulfate (MgSO₄), & calcium carbonate (CaCO₃)

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The first electron lost is from 5s not 4d!
Thallium loses these 3
electrons to form Tl3+
which is an 18-electron
configuration
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﷟HYPERLINK "https://ptable.com/#Properties/Radius/Calculated"Atomic Radius 
The size of the atom from the nucleus to the outermost (valence) electron
Untitled picture.emf 8 
(G 
(ğ fiğ 






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Increases down a group b/c
of an increase in shell number
Decreases across a period because electron shielding is not as effective in the same shell
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 The effective nuclear charge (Zeff) is 
only +1 for the Valence electron 
of potassium

The shielding by the other 18 electrons
Negates most of the nuclear charge!







When an electron is more attracted to the nucleus, the atomic radius is smaller
Atomic vs Ionic Radii

Sodium atom
Na
Sodium ion
Na+
Radius
1.54 A
 0.97 A
Protons
11
11
Electrons
11
10

We've stripped our outer valence electron for sodium, and now the ion is much smaller compared to the neutral atom. The nuclear charge is greater than the sum of the electron charges so the remaining electrons get pulled in more to the nucleus. Cations are smaller


Untitled picture.emf Group IA 
Group 2A 
Group 3A 
133+ B 
0.23 082 
A13+ Al 
0.51 1.18 
Ga3• Ga 
0.62 126 
In3+ In 
0.81 1.44 
Group 6A 
Group 7A 
0.68 
Li 
1.34 
Be2+ 
0.31 
Mg2• 
Be 
0.90 
o 
0.73 
02 ¯ 
1.40 
0.71 
1.33 
0.97 1.54 
1.33 1.96 
Rb 
2.11 
1.47 
Mg 
0.66 1.30 
0.99 1.74 
Sr2+ Sr 
1.13 
1.92 
1.02 184 
Se se2- 
1.16 
1.98 
1.35 
2.21 
1.81 
1.14 
1.96 
1.33 
2.20 
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However the effective nuclear charge for calcium is +2 as the other valence electron doesn't help shield it. Therefore the valence electrons are pulled in more resulting in the radius decreasing
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Chlorine atom
Cl
Chloride ion
Cl–
Radius
0.99 A
1.81 A
Protons
 17
17
Electrons
17
18


We have an excess of electrons. Now these electrons aren't going to feel the charge of the nucleus as much. This results in the radius getting much larger. There are more electrons, resulting in more electron-electron repulsion this makes the radius get larger as well. Anions are larger
Untitled picture.emf Group IA 
Group 2A 
Group 3A 
133+ B 
0.23 082 
A13+ Al 
0.51 1.18 
Ga3• Ga 
0.62 126 
In3+ In 
0.81 1.44 
Group 6A 
Group 7A 
0.68 
Li 
1.34 
Be2+ 
0.31 
Mg2• 
Be 
0.90 
o 
0.73 
02 ¯ 
1.40 
0.71 
1.33 
0.97 1.54 
1.33 1.96 
Rb 
2.11 
1.47 
Mg 
0.66 1.30 
0.99 1.74 
Sr2+ Sr 
1.13 
1.92 
1.02 184 
Se se2- 
1.16 
1.98 
1.35 
2.21 
1.81 
1.14 
1.96 
1.33 
2.20 

﷟HYPERLINK "https://www.geo.arizona.edu/xtal/geos596a/ACA32_751.pdf"a12967.pdf (arizona.edu)


Practice Predicting Trends for Isoelectronic Species


Oxide ion
O2–
Fluoride ion
F–
Neon
Ne
Sodium ion
Na+
Magnesium ion
Mg2+
Covalent Radius (Å)
1.40
1.33
0.67
0.97
0.66
Protons
8
9
10
11
12
Electrons
10
10
10
10
10






Naming Ionic Compounds
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There is a system to naming compounds known as nomenclature
Ionic compounds are named based on the composition and charge of the ions involved

Step 1: Name the cation (positive ion)

For elements: simply use the element's name.

For Transition metals: indicate the ion's charge with Roman numerals in parentheses if it is variable.

Step 2: Name the anion (negative ion)

For single element ions: Take the element's root name and add the suffix "-ide".

For polyatomic ions: Use the ion's common name.

Step 3: Combining the cation and anion

Write the name of the cation first, followed by the name of the anion.
Do not specify the number of ions in the name as the formula should already be 
the simplest ratio that results in a neutral compound

Examples:
Chemical Formula
Cation
Anion
Name
 
CaO 




 
CaCl2




 
CuCl





 




Extra practice 
NaCl
MgBr₂
Al₂O₃
FeCl₃
CaCO₃
K₂SO₄
Cu(NO₃)₂
Zn(OH)₂
Ag₂S
NH₄Cl
Even more practice
Ba(OH)₂
Na₂S
CaF₂
KNO₃
MnO₂
Li₃PO₄
CoCl₂
NiSO₄
Sr(NO₃)₂
Al(C₂H₃O₂)₃
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FeCO3



Untitled picture.png Metals with one common 
ionic charge 
Group 1 metals: 
Group 2 metals: 
all +1; e.g., Na+ 
all +2; e.g., Mg2+ 
Ni2* 
Metals with two common 
ionic charges 
Au+ and Au3+ 
Cu+ and Cu2+ 
and Hg2+ 
Pb2+ and 
Sn2+ and Sn4+ 
c02 + and C03+ 
Fe2+ and Fe3+ 
Tl+ and T13+ 
Sb3+ and Sb3+ 
Ti3+ and Ti4+ 
Metals with three common 
ionic charges 
C++ Cr*+ Cr6+ 
Mn2+ Mn4+ Mn7+ 
Untitled picture.png Metal 
copper 
gold 
Iron 
lead 
mercury 
tm 
Ionic charge 
+1 
+2 
+1 
+3 
+2 
+3 
+2 
+4 
+1 
+2 
+2 
+4 
Symbols 
Fe2+ 
Modern systematic 
(IUPAC) names 
copper(l) 
copper(ll) 
gold (I) 
gold(lll) 
iron (Il) 
iron (Ill) 
lead (11) 
lead (IV) 
mercury(l)* 
mercury (Il) 
tin (11) 
tin (IV) 
Old names 
cuprous 
cupric 
aurous 
aunc 
plumb ous 
plumbic 
mercurous 
mercuric 
stannous 
stannic 



Writing the Formula of Ionic Compounds
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Writing the Formula of Ionic Compounds
Writing the formula for ionic compounds requires understanding the charges of the ions involved and how they should combine to be neutral.
Use the ﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28699/modules/items/2876744"periodic chart of the ions handout to help you learn the charges. Transition metals are often variable.
The ﷟HYPERLINK "https://boisestatecanvas.instructure.com/courses/28699/modules/items/2985506"method of charge crossing is the easiest approach.

Step 1: Identify the ions

Cations (positive ions): Usually the metal or the polyatomic ammonium ion (NH4+). The name of the cation is the element unless it’s a transition metal that can have more than one charge, then its name is specified with Roman numerals.

Anions (negative ions): They can be nonmetals which end in "-ide" or polyatomic ions (like sulfate, nitrite, acetate)

Step 2: Determine the charges

Use the ion table to determine the charge of each ion. Many of these should be committed to memory. For example, the group 1 elements form +1, group 2 elements form +2, and aluminum forms +3. Commonly used polyatomics like phosphate and nitrate are very common and knowing their charges and formulas (-3 and -1 respectively) are helpful.

Step 3: Balance the charges

The total positive charge must balance the total negative charge. 
Simplest approach: Cross superscripts to subscripts, then divide through by any common factor.

Step 4: Write the formula

Write the symbol of the cation first, followed by the symbol of the anion.
If more than one of a particular ion is needed to balance the charge, use a subscript to indicate the number of ions. 
Do not use a subscript for a single ion. 
For polyatomic ions that need a subscript, place the polyatomic ion in parentheses before adding the subscript.



Examples:
Name
Cation
Anion
Chemical Formula
 
sodium oxide



Extra Practice
Potassium chloride
Magnesium oxide
Even more practice
Sodium bicarbonate
Potassium permanganate
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sodium oxide

 
aluminum acetate




 
calcium phosphate



     
 
iron(II) oxide



   
Magnesium oxide
Calcium sulfate
Aluminum nitrate
Sodium phosphate
Ammonium chloride
Iron(III) bromide
Copper(II) carbonate
Barium hydroxide
Lithium sulfide

Potassium permanganate
Zinc sulfate
Lead(II) nitrate
Cesium chloride
Silver iodide
Nickel(II) phosphate
Calcium hydroxide
Ammonium sulfate
Strontium chromate

e– Configurations of Transition Metals Ions
The filling order of transition metal ions follows a regular pattern:
1s < 2s < 2p < 3s < 3p < 3d < 4s < 4d < 4f < . . . 
The removal of a valence electron changes the energy levels of these subshells so that they differ from their neutral atom
This is the reason why nearly all transition metals lose their first valence electron from the s orbital, not the d orbital
What is the ground state electron configurations of the Cr(II), Cr(III), and Cr(VI) ions?








Diamagnetism vs Paramagnetism
Diamagnetic and paramagnetic materials are distinguished by their responses to magnetic fields, which can be related to the electronic configuration of atoms or ions, particularly in transition metal ions. 
Diamagnetic materials are characterized by the absence of unpaired electrons in their electron shells. When placed in a magnetic field, diamagnetic materials induce a magnetic moment that is weak and in the opposite direction to the applied field.
For example, Zn2+ has a completely filled d subshell 3d10 with all electrons paired, making it diamagnetic.




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Paramagnetic materials, on the other hand, have one or more unpaired electrons. These unpaired electrons have intrinsic magnetic moments due to their spin, and when an external magnetic field is applied, these moments tend to align with the field, making the material magnetically attractive. 
For instance, Fe3+ has five unpaired electrons 3d5, making it strongly paramagnetic.







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